Outcore Code solutions level 4 to 7

Outcore Code solutions level 4 to 7 1 - steamsplay.com
Outcore Code solutions level 4 to 7 1 - steamsplay.com

This guide provides all the code solutions from level 4 to???. ?
 

Introduction

About myself:
 
I am a self-taught programmer who loves optimizing code. You can trust me!
 
 
About this guide:
 
First of all, if you're new at coding, I highly recommend that it be tried. It's so much fun and easy.
 
This guide was created to help me save my own code for the mini-coding game.
 
This guide will include codes for levels 4 to ????. This guide will have codes for levels 4 to????
 
 
Notes:
 
I hate JavaScript <3
 
All levels require that you have three functions: MoveForward(); TurnRight(); DoNothing()
 
So I'll only write those additional functions that i didn’t mention here
 
 
Last but not least, please like this:>
 
Outcore Code solutions level 4 to 7 - Introduction - AAC27F8
 
 
 

Level 4

Additional Functions needed:
 
None
 
 
Note:
 
You can change the while loop number to determine how many coins are needed.
 
 
Code:
 
 

// to get to our initial point
Turn(2)
Move(2)

// coins we collected so far
var coins = 0;
// we need 35 to buy the key
while(coins < 35)
{
 // go throught the maze
 Move(8)
 Turn(3)
 Move(3)
 Turn(3)
 Move(8)

 // collect the coins
 Wait(5)
 coins+=5;

 // return to the initial position
 Turn(3)
 Move(3)
 Turn(3)
}

// functions to simplify my life
function Move(x){
 for (let i = 0; i < x; i++) {
 MoveForward()
 }
}

function Turn(x){
 for (let i = 0; i < x; i++) {
 TurnRight()
 }
}

function Wait(x){
 for (let i = 0; i < x; i++) {
 DoNothing()
 }
}

 
 
 

Level 5

Additional Functions needed:
 
None
 
 
Note:
 
This code is too slow to execute if your goal is to buy everything
 
 
Code:
 
 

// get to the initial position
Turn(3)
Move(1)
Turn(1)
Move(4)

// current amount coins held
var coins = 0;

// start the grind
while(coins < 250)
{
 Turn(1)
 Move(4)
 Turn(1)
 Move(3)
 Turn(3)
 Move(1)
 Turn(1)
 Move(7)
 Turn(3)
 Move(2)
 Turn(2)
 Move(7)
 Turn(1)

 // got to the bank and deposit your money
 Move(4)
 Wait(5)
 coins += 5

 // back to where we started
 Move(6)
}

// functions to simplify my life
function Move(x){
 for (let i = 0; i < x; i++) {
 MoveForward()
 }
}

function Turn(x){
 for (let i = 0; i < x; i++) {
 TurnRight()
 }
}

function Wait(x){
 for (let i = 0; i < x; i++) {
 DoNothing()
 }
}

 
 
 

Level 6

Additional Functions needed:
 
– GetWorkerInventoryItems()
 
 
Note:
 
This is the first stage of the process where you will have 2 workers to manage. I'll provide 2 code blocks for each worker.
 
– This stage can be completed with 1 worker if desired. Simply make the first worker loop until it has collected 1000 coins.
 
 
Code:
 
Worker 1:
 
 

// get to the initial position
Move(5)
Turn(3)

var coins = 0
while(coins < 500){
 Move(13)
 Turn(3)
 Move(5)

 // deposit
 var coinsCollected = GetWorkerInventoryItems().length
 Wait(coinsCollected)
 coins += coinsCollected

 Move(5)
 Turn(3)
 Move(16)
 Turn(3)
 Move(10)
 Turn(3)
 Move(3)
}

// when done get out of the way so the other worker can finish it's work
Turn(1)
Move(1)


// functions to simplify my life
function Move(x){
 for (let i = 0; i < x; i++) {
 MoveForward()
 }
}

function Turn(x){
 for (let i = 0; i < x; i++) {
 TurnRight()
 }
}

function Wait(x){
 for (let i = 0; i < x; i++) {
 DoNothing()
 }
}

 
 
Worker 2:
 
 

// Get to the initial position
Move(5)
Turn(3)

var coins = 0
while(coins < 500){
 Move(10)
 Turn(3)
 Move(10)
 Turn(3)
 Move(16)
 Turn(3)
 Move(5)

 // deposit
 var coinsCollected = GetWorkerInventoryItems().length
 Wait(coinsCollected)
 coins += coinsCollected

 Move(5)
 Turn(3)
 Move(6)
}

// when done get out of the way so the other worker can finish it's work
Turn(1)
Move(1)


// functions to simplify my life
function Move(x){
 for (let i = 0; i < x; i++) {
 MoveForward()
 }
}

function Turn(x){
 for (let i = 0; i < x; i++) {
 TurnRight()
 }
}

function Wait(x){
 for (let i = 0; i < x; i++) {
 DoNothing()
 }
}

 
 
 

Level 7

Additional Functions needed:
 
– SyncWorkers()
 
 
Note:
 
Although this is not the best way, it's the only way I know.
 
 
Code:
 
worker 1
 
 

// get to the initial position
Move(5)
Turn(1)
Move(1)

while(true){
 Move(2)
 Turn(2)
 if (SyncWorkers()){
 break
 }
}

// functions to simplify my life
function Move(x){
 for (let i = 0; i < x; i++) {
 MoveForward()
 }
}

function Turn(x){
 for (let i = 0; i < x; i++) {
 TurnRight()
 }
}

function Wait(x){
 for (let i = 0; i < x; i++) {
 DoNothing()
 }
}

 
 
worker 2:
 
 

// get to the initial position
Turn(1)

var coins = -1
while (coins < 2400){
 Move(7)
 Turn(3)
 Move(2)
 Turn(3)
 Move(3)
 Turn(3)
 Move(2)
 Turn(1)
 Move(6)
 // deposit
 Wait(6)
 coins += 6
 Turn(2)
 Move(2)
}

while(true){
 if (SyncWorkers()){
 break
 }
}

// functions to simplify my life
function Move(x){
 for (let i = 0; i < x; i++) {
 MoveForward()
 }
}

function Turn(x){
 for (let i = 0; i < x; i++) {
 TurnRight()
 }
}

function Wait(x){
 for (let i = 0; i < x; i++) {
 DoNothing()
 }
}

 
 

Written by cabiste

 
 
Hope you enjoy the post for Outcore Code solutions level 4 to 7, If you think we should update the post or something is wrong please let us know via comment and we will fix it how fast as possible! Thank you and have a great day!
 


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